ACPI: Do not fail acpi_bind_one() if device is already bound correctly

Modify acpi_bind_one() so that it doesn't fail if the device
represented by its first argument has already been bound to the
given ACPI handle (second argument), because that is not a good
enough reason for returning an error code.

Signed-off-by: Rafael J. Wysocki <rafael.j.wysocki@intel.com>
Reviewed-by: Lan Tianyu <tianyu.lan@intel.com>
Acked-by: Toshi Kani <toshi.kani@hp.com>
This commit is contained in:
Rafael J. Wysocki 2013-08-07 01:15:25 +02:00
parent 69fdadfd22
commit 3fe444ad7e

View File

@ -217,7 +217,10 @@ int acpi_bind_one(struct device *dev, acpi_handle handle)
/* Sanity check. */
if (pn->dev == dev) {
dev_warn(dev, "Already associated with ACPI node\n");
goto err_free;
if (ACPI_HANDLE(dev) == handle)
retval = 0;
goto out_free;
}
if (pn->node_id == node_id) {
physnode_list = &pn->node;
@ -255,10 +258,14 @@ int acpi_bind_one(struct device *dev, acpi_handle handle)
put_device(dev);
return retval;
err_free:
out_free:
mutex_unlock(&acpi_dev->physical_node_lock);
kfree(physical_node);
goto err;
if (retval)
goto err;
put_device(dev);
return 0;
}
EXPORT_SYMBOL_GPL(acpi_bind_one);