of: Allow mem_reserve of memory with a base address of zero

__reserved_mem_reserve_reg() won't reserve memory if the base address
is zero. This change removes the check for a base address of zero and
allows it to be reserved.

Allowing the first 4K of memory to be reserved will help solve a
problem on some ARM systems where the the first 16K of memory is
unused and becomes allocable memory. This will prevent this memory
from being used for DMA by drivers like the USB OHCI driver which
consider a physical address of zero to be illegal.

Cc: stable@vger.kernel.org # 3.15+
Signed-off-by: Al Cooper <alcooperx@gmail.com>
Signed-off-by: Grant Likely <grant.likely@linaro.org>
This commit is contained in:
Al Cooper 2014-08-06 16:30:04 -04:00 committed by Grant Likely
parent c9d26423e5
commit b5f2a8c026

View File

@ -453,7 +453,7 @@ static int __init __reserved_mem_reserve_reg(unsigned long node,
base = dt_mem_next_cell(dt_root_addr_cells, &prop);
size = dt_mem_next_cell(dt_root_size_cells, &prop);
if (base && size &&
if (size &&
early_init_dt_reserve_memory_arch(base, size, nomap) == 0)
pr_debug("Reserved memory: reserved region for node '%s': base %pa, size %ld MiB\n",
uname, &base, (unsigned long)size / SZ_1M);