SPI: use mutex not semaphore

Make spi_write_then_read() use a mutex not a binary semaphore.

Signed-off-by: David Brownell <dbrownell@users.sourceforge.net>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
This commit is contained in:
David Brownell 2007-12-04 23:45:09 -08:00 committed by Linus Torvalds
parent f8fcc93319
commit 068f407086

View File

@ -589,7 +589,7 @@ int spi_write_then_read(struct spi_device *spi,
const u8 *txbuf, unsigned n_tx,
u8 *rxbuf, unsigned n_rx)
{
static DECLARE_MUTEX(lock);
static DEFINE_MUTEX(lock);
int status;
struct spi_message message;
@ -615,7 +615,7 @@ int spi_write_then_read(struct spi_device *spi,
}
/* ... unless someone else is using the pre-allocated buffer */
if (down_trylock(&lock)) {
if (!mutex_trylock(&lock)) {
local_buf = kmalloc(SPI_BUFSIZ, GFP_KERNEL);
if (!local_buf)
return -ENOMEM;
@ -634,7 +634,7 @@ int spi_write_then_read(struct spi_device *spi,
}
if (x[0].tx_buf == buf)
up(&lock);
mutex_unlock(&lock);
else
kfree(local_buf);