perf: arm-spe: Fix check error when synthesizing events

In arm_spe_read_record(), when we are processing an events packet,
'decoder->packet.index' is the length of payload, which has been
transformed in payloadlen(). So correct the check of 'idx'.

Signed-off-by: Wei Li <liwei391@huawei.com>
Reviewed-by: Leo Yan <leo.yan@linaro.org>
Cc: Alexander Shishkin <alexander.shishkin@linux.intel.com>
Cc: Hanjun Guo <guohanjun@huawei.com>
Cc: James Clark <james.clark@arm.com>
Cc: Jiri Olsa <jolsa@redhat.com>
Cc: Mark Rutland <mark.rutland@arm.com>
Cc: Mathieu Poirier <mathieu.poirier@linaro.org>
Cc: Namhyung Kim <namhyung@kernel.org>
Cc: Peter Zijlstra <peterz@infradead.org>
Link: http://lore.kernel.org/lkml/20200724072628.35904-1-liwei391@huawei.com
Signed-off-by: Arnaldo Carvalho de Melo <acme@redhat.com>
This commit is contained in:
Wei Li 2020-07-24 15:26:28 +08:00 committed by Arnaldo Carvalho de Melo
parent 783abbd444
commit 19684e969d

View File

@ -182,15 +182,15 @@ static int arm_spe_read_record(struct arm_spe_decoder *decoder)
if (payload & BIT(EV_TLB_ACCESS))
decoder->record.type |= ARM_SPE_TLB_ACCESS;
if ((idx == 1 || idx == 2 || idx == 3) &&
if ((idx == 2 || idx == 4 || idx == 8) &&
(payload & BIT(EV_LLC_MISS)))
decoder->record.type |= ARM_SPE_LLC_MISS;
if ((idx == 1 || idx == 2 || idx == 3) &&
if ((idx == 2 || idx == 4 || idx == 8) &&
(payload & BIT(EV_LLC_ACCESS)))
decoder->record.type |= ARM_SPE_LLC_ACCESS;
if ((idx == 1 || idx == 2 || idx == 3) &&
if ((idx == 2 || idx == 4 || idx == 8) &&
(payload & BIT(EV_REMOTE_ACCESS)))
decoder->record.type |= ARM_SPE_REMOTE_ACCESS;