vsprintf: fix io/mem resource width
The leading "0x" consumes field width, so leave space for it in addition to the 4 or 8 hex digits. This means we'll print "0x0000-0x01df" rather than "0x00-0x1df", for example. Signed-off-by: Bjorn Helgaas <bjorn.helgaas@hp.com> Signed-off-by: Jesse Barnes <jbarnes@virtuousgeek.org>
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@ -598,11 +598,11 @@ static char *resource_string(char *buf, char *end, struct resource *res,
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struct printf_spec spec)
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{
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#ifndef IO_RSRC_PRINTK_SIZE
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#define IO_RSRC_PRINTK_SIZE 4
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#define IO_RSRC_PRINTK_SIZE 6
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#endif
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#ifndef MEM_RSRC_PRINTK_SIZE
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#define MEM_RSRC_PRINTK_SIZE 8
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#define MEM_RSRC_PRINTK_SIZE 10
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#endif
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struct printf_spec num_spec = {
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.base = 16,
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