perf sched: Fix nsec to msec conversion
We are dividing a time in ns by 1e9. This is a nsec to sec conversion. What we want is msecs. Fix it by dividing by 1e6. Signed-off-by: Frederic Weisbecker <fweisbec@gmail.com> Cc: Peter Zijlstra <a.p.zijlstra@chello.nl> Cc: Mike Galbraith <efault@gmx.de> Cc: Paul Mackerras <paulus@samba.org> Cc: Arnaldo Carvalho de Melo <acme@redhat.com> Signed-off-by: Ingo Molnar <mingo@elte.hu>
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@ -1129,9 +1129,9 @@ static void output_lat_thread(struct task_atoms *atom_list)
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avg = atom_list->total_lat / atom_list->nb_atoms;
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printf("|%9.3f ms |%9llu | avg:%9.3f ms | max:%9.3f ms |\n",
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(double)atom_list->total_runtime / 1e9,
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atom_list->nb_atoms, (double)avg / 1e9,
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(double)atom_list->max_lat / 1e9);
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(double)atom_list->total_runtime / 1e6,
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atom_list->nb_atoms, (double)avg / 1e6,
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(double)atom_list->max_lat / 1e6);
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}
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static void __cmd_lat(void)
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@ -1157,7 +1157,7 @@ static void __cmd_lat(void)
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printf("-----------------------------------------------------------------------------------\n");
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printf(" TOTAL: |%9.3f ms |%9Ld |\n",
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(double)all_runtime/1e9, all_count);
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(double)all_runtime/1e6, all_count);
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printf("---------------------------------------------\n");
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}
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