[PATCH] x86: remove last two pci_find offenders in the core code
Resending as I believe the discussion about them established they were correct. Signed-off-by: Alan Cox <alan@redhat.com> Signed-off-by: Andi Kleen <ak@suse.de> Cc: Andi Kleen <ak@suse.de> Signed-off-by: Andrew Morton <akpm@osdl.org>
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@ -764,7 +764,7 @@ static void __init pirq_find_router(struct irq_router *r)
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DBG(KERN_DEBUG "PCI: Attempting to find IRQ router for %04x:%04x\n",
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rt->rtr_vendor, rt->rtr_device);
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pirq_router_dev = pci_find_slot(rt->rtr_bus, rt->rtr_devfn);
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pirq_router_dev = pci_get_bus_and_slot(rt->rtr_bus, rt->rtr_devfn);
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if (!pirq_router_dev) {
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DBG(KERN_DEBUG "PCI: Interrupt router not found at "
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"%02x:%02x\n", rt->rtr_bus, rt->rtr_devfn);
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@ -784,6 +784,8 @@ static void __init pirq_find_router(struct irq_router *r)
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pirq_router_dev->vendor,
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pirq_router_dev->device,
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pci_name(pirq_router_dev));
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/* The device remains referenced for the kernel lifetime */
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}
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static struct irq_info *pirq_get_info(struct pci_dev *dev)
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@ -921,7 +921,7 @@ static int __init calgary_init(void)
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error:
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do {
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dev = pci_find_device_reverse(PCI_VENDOR_ID_IBM,
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dev = pci_get_device_reverse(PCI_VENDOR_ID_IBM,
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PCI_DEVICE_ID_IBM_CALGARY,
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dev);
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if (!dev)
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