timer: Try to survive timer callback preempt_count leak
If a timer callback leaks preempt_count we currently assert a BUG(). That makes it unnecessarily hard to retrieve information about the problem especially on laptops and headless stations. There is a decent chance to survive the preempt_count leak by restoring the preempt_count to the value before the callback. That allows in many cases to get valuable information about the root cause of the problem. We carried that fixup in preempt-rt for years and were able to decode such wreckage quite a few times. Signed-off-by: Thomas Gleixner <tglx@linutronix.de> Cc: Linux Torvalds <torvalds@linux-foundation.org> Cc: Andrew Morton <akpm@linux-foundation.org> Cc: Arjan van de Veen <arjan@infradead.org>
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@ -982,9 +982,15 @@ static void call_timer_fn(struct timer_list *timer, void (*fn)(unsigned long),
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lock_map_release(&lockdep_map);
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if (preempt_count != preempt_count()) {
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printk(KERN_ERR "timer: %pF preempt leak: %08x -> %08x\n",
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fn, preempt_count, preempt_count());
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BUG();
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WARN_ONCE(1, "timer: %pF preempt leak: %08x -> %08x\n",
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fn, preempt_count, preempt_count());
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/*
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* Restore the preempt count. That gives us a decent
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* chance to survive and extract information. If the
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* callback kept a lock held, bad luck, but not worse
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* than the BUG() we had.
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*/
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preempt_count() = preempt_count;
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}
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}
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