sched/deadline: Remove unnecessary condition in push_dl_task()
pick_next_pushable_dl_task(rq) has BUG_ON(rq->cpu != task_cpu(task)) when it returns a task other than NULL, which means that task_cpu(task) must be rq->cpu. So if task == next_task, then task_cpu(next_task) must be rq->cpu as well. Remove the redundant condition and make the code simpler. This way one unnecessary branch and two LOAD operations can be avoided. Signed-off-by: Byungchul Park <byungchul.park@lge.com> Signed-off-by: Peter Zijlstra (Intel) <peterz@infradead.org> Reviewed-by: Steven Rostedt (VMware) <rostedt@goodmis.org> Reviewed-by: Juri Lelli <juri.lelli@arm.com> Reviewed-by: Daniel Bristot de Oliveira <bristot@redhat.com> Cc: <kernel-team@lge.com> Cc: Linus Torvalds <torvalds@linux-foundation.org> Cc: Peter Zijlstra <peterz@infradead.org> Cc: Thomas Gleixner <tglx@linutronix.de> Link: http://lkml.kernel.org/r/1494551159-22367-1-git-send-email-byungchul.park@lge.com Signed-off-by: Ingo Molnar <mingo@kernel.org>
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@ -1533,7 +1533,7 @@ static int push_dl_task(struct rq *rq)
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* then possible that next_task has migrated.
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*/
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task = pick_next_pushable_dl_task(rq);
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if (task_cpu(next_task) == rq->cpu && task == next_task) {
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if (task == next_task) {
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/*
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* The task is still there. We don't try
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* again, some other cpu will pull it when ready.
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