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scripts/gdb: decode bytestream on dmesg for Python3

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The recent fixes to lx-dmesg, now allow the command to print
successfully on Python3, however the python interpreter wraps the bytes
for each line with a b'<text>' marker.

To remove this, we need to decode the line, where .decode() will default
to 'UTF-8'

Link: http://lkml.kernel.org/r/d67ccf93f2479c94cb3399262b9b796e0dbefcf2.1462865983.git.jan.kiszka@siemens.com
Signed-off-by: Kieran Bingham <kieran@bingham.xyz>
Acked-by: Dom Cote <buzdelabuz2@gmail.com>
Tested-by: Dom Cote <buzdelabuz2@gmail.com>
Signed-off-by: Jan Kiszka <jan.kiszka@siemens.com>
Signed-off-by: Andrew Morton <akpm@linux-foundation.org>
Signed-off-by: Linus Torvalds <torvalds@linux-foundation.org>
This commit is contained in:
Kieran Bingham 2016-05-23 16:25:21 -07:00 committed by Linus Torvalds
parent d21d5b9eb0
commit b3b0842985
1 changed files with 2 additions and 2 deletions
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4
scripts/gdb/linux/dmesg.py
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@ -51,10 +51,10 @@ class LxDmesg(gdb.Command):
continue
text_len = utils.read_u16(log_buf[pos + 10:pos + 12])
text = log_buf[pos + 16:pos + 16 + text_len]
text = log_buf[pos + 16:pos + 16 + text_len].decode()
time_stamp = utils.read_u64(log_buf[pos:pos + 8])
for line in memoryview(text).tobytes().splitlines():
for line in text.splitlines():
gdb.write("[{time:12.6f}] {line}\n".format(
time=time_stamp / 1000000000.0,
line=line))