[SCSI] libfc: Fix misleading debug statement
The statement reads, "Exchange timed out, notifying the upper layer", however, this statement is printed whenever the timer is armed. This is confusing to someone debugging the code because every time an exchange is initialized, there is an incorrect statement stating that the timer has already timed out. This patch changes the statement to read, "Exchange timer armed" which is more accurate. This patch also adds a debug statement in the timeout handler to properly indicate that the exchange has timed out. Signed-off-by: Robert Love <robert.w.love@intel.com> Signed-off-by: James Bottomley <James.Bottomley@suse.de>
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@ -326,7 +326,7 @@ static inline void fc_exch_timer_set_locked(struct fc_exch *ep,
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if (ep->state & (FC_EX_RST_CLEANUP | FC_EX_DONE))
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return;
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FC_EXCH_DBG(ep, "Exchange timed out, notifying the upper layer\n");
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FC_EXCH_DBG(ep, "Exchange timer armed\n");
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if (schedule_delayed_work(&ep->timeout_work,
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msecs_to_jiffies(timer_msec)))
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@ -412,6 +412,8 @@ static void fc_exch_timeout(struct work_struct *work)
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u32 e_stat;
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int rc = 1;
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FC_EXCH_DBG(ep, "Exchange timed out\n");
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spin_lock_bh(&ep->ex_lock);
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if (ep->state & (FC_EX_RST_CLEANUP | FC_EX_DONE))
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goto unlock;
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