bfq-iosched: Revert "bfq: Fix computation of shallow depth"
[ Upstream commit 388c705b95f23f317fa43e6abf9ff07b583b721a ] This reverts commit 6d4d273588378c65915acaf7b2ee74e9dd9c130a. bfq.limit_depth passes word_depths[] as shallow_depth down to sbitmap core sbitmap_get_shallow, which uses just the number to limit the scan depth of each bitmap word, formula: scan_percentage_for_each_word = shallow_depth / (1 << sbimap->shift) * 100% That means the comments's percentiles 50%, 75%, 18%, 37% of bfq are correct. But after commit patch 'bfq: Fix computation of shallow depth', we use sbitmap.depth instead, as a example in following case: sbitmap.depth = 256, map_nr = 4, shift = 6; sbitmap_word.depth = 64. The resulsts of computed bfqd->word_depths[] are {128, 192, 48, 96}, and three of the numbers exceed core dirver's 'sbitmap_word.depth=64' limit nothing. Signed-off-by: Lin Feng <linf@wangsu.com> Reviewed-by: Jan Kara <jack@suse.cz> Signed-off-by: Jens Axboe <axboe@kernel.dk> Signed-off-by: Sasha Levin <sashal@kernel.org>
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@ -6332,13 +6332,13 @@ static unsigned int bfq_update_depths(struct bfq_data *bfqd,
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* limit 'something'.
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*/
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/* no more than 50% of tags for async I/O */
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bfqd->word_depths[0][0] = max(bt->sb.depth >> 1, 1U);
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bfqd->word_depths[0][0] = max((1U << bt->sb.shift) >> 1, 1U);
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/*
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* no more than 75% of tags for sync writes (25% extra tags
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* w.r.t. async I/O, to prevent async I/O from starving sync
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* writes)
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*/
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bfqd->word_depths[0][1] = max((bt->sb.depth * 3) >> 2, 1U);
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bfqd->word_depths[0][1] = max(((1U << bt->sb.shift) * 3) >> 2, 1U);
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/*
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* In-word depths in case some bfq_queue is being weight-
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@ -6348,9 +6348,9 @@ static unsigned int bfq_update_depths(struct bfq_data *bfqd,
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* shortage.
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*/
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/* no more than ~18% of tags for async I/O */
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bfqd->word_depths[1][0] = max((bt->sb.depth * 3) >> 4, 1U);
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bfqd->word_depths[1][0] = max(((1U << bt->sb.shift) * 3) >> 4, 1U);
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/* no more than ~37% of tags for sync writes (~20% extra tags) */
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bfqd->word_depths[1][1] = max((bt->sb.depth * 6) >> 4, 1U);
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bfqd->word_depths[1][1] = max(((1U << bt->sb.shift) * 6) >> 4, 1U);
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for (i = 0; i < 2; i++)
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for (j = 0; j < 2; j++)
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