ae02c0008c
[ Upstream commit 4025c784c573cab7e3f84746cc82b8033923ec62 ]
When an asynchronous interrupt calls irq_exit, it checks for softirqs
that may have been created, and runs them. Running softirqs enables
local irqs, which can replay pending interrupts causing recursion in
replay_soft_interrupts. This abridged trace shows how this can occur:
! NIP replay_soft_interrupts
LR interrupt_exit_kernel_prepare
Call Trace:
interrupt_exit_kernel_prepare (unreliable)
interrupt_return
--- interrupt: ea0 at __rb_reserve_next
NIP __rb_reserve_next
LR __rb_reserve_next
Call Trace:
ring_buffer_lock_reserve
trace_function
function_trace_call
ftrace_call
__do_softirq
irq_exit
timer_interrupt
! replay_soft_interrupts
interrupt_exit_kernel_prepare
interrupt_return
--- interrupt: ea0 at arch_local_irq_restore
This can not be prevented easily, because softirqs must not block hard
irqs, so it has to be dealt with.
The recursion is bounded by design in the softirq code because softirq
replay disables softirqs and loops around again to check for new
softirqs created while it ran, so that's not a problem.
However it does mess up interrupt replay state, causing superfluous
interrupts when the second replay_soft_interrupts clears a pending
interrupt, leaving it still set in the first call in the 'happened'
local variable.
Fix this by not caching a copy of irqs_happened across interrupt
handler calls.
Fixes:
|
||
---|---|---|
.. | ||
alpha | ||
arc | ||
arm | ||
arm64 | ||
c6x | ||
csky | ||
h8300 | ||
hexagon | ||
ia64 | ||
m68k | ||
microblaze | ||
mips | ||
nds32 | ||
nios2 | ||
openrisc | ||
parisc | ||
powerpc | ||
riscv | ||
s390 | ||
sh | ||
sparc | ||
um | ||
x86 | ||
xtensa | ||
.gitignore | ||
Kconfig |